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What happens when you attempt to compile and run the following code?
#include
using namespace std;
int main()
{
cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main () {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
vector
int number = count(v.begin(), v.end(), 2);
cout<< number< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a) : a(a) {}
int getA() const { return a; } void setA(int a) { this?>a = a; }
bool operator < (const A & b) const { return a }; struct Compare { bool operator ()(A & a) { if (a.getA() < 5) return true; return false; } }; int main () { int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5}; set d (t,t+15); int number = count_if(d.begin(), d.end(), Compare()); cout<< number< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< struct Add { int operator()(int & a, int & b) { return a+b; } }; int main() { int t[]={1,2,3,4,5,6,7,8,9,10}; vector vector transform(v1.begin(), v1.end(), v2.begin(), bind2nd(Add(),1)); for_each(v2.rbegin(), v2.rend(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
class A {
public:
virtual int f() { return 10; }
virtual ~A(){}
};
class B: public A {
int f() {return 11; }
virtual ~B(){}
};
int main (){
std::vectorv1;
for(int i = 10; i>0; i??)
{
i%2>0?v1.push_back(new A()):v1.push_back(new B());
}
std::vector::iterator it = v1.begin();
while(it != v1.end())
{
std::cout<
v1.pop_back();++it;
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { string t[]={"aaa","Aaa", "aAa","aaA","bbb","Bbb", "bBb", "bbB"}; vector sort(v1.begin(), v1.end()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
Which lines of the code below contain proper instantiation of queue objects?
#include
#include
#include
#include
#include
using namespace std;
int main()
{
deque
list
vector
queue
queue
queue
queue
queue
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
bool identical(int a, int b) {
return b == 2*a?true:false;
}
int main() {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
int u[] = {2,4,6,4,6,10,2,4,14,6,4,2,20,8,8,5};
vector
deque
pair
result = mismatch(d1.begin(), d1.end(), v1.begin(), identical); //Line I
if (result.first == d1.end() && result.second == v1.end()) {//Line II
cout<<"Identical\n";
} else {
cout<<"Not identical\n";
}
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; deque deque for_each(it, d1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
using namespace std;
void g(int a)
{
cout< } template void g(A a) {
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main () {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
vector
vector
cout<< it?v.begin()< return 0; } Program outputs:
Which sentence is correct about the code below? Choose all that apply.
#include
#include
#include
using namespace std;
class F {
int val;
public:
F(int v):val(v){}
bool operator() (int v) {
if (v == val) return true;
return false;
}
};
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
if (find(v1.begin(), v1.end(), 6) == find(v1.begin(), v1.end(), F(6))) {
cout<<"Found!\n";
} else {
cout<<"Not found!\n";
}
return 0;
}
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: 1 2 3 end
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { list for( ; !cin.bad() ; ) { int i; cin>>i; l.push_back(i); } for_each(l.begin(), l.end(), Out return 0; } Program will output:
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: 1.1 2.2 3.3
#include
#include
using namespace std;
int main ()
{
int a,b,c;
cin>>a>>b>>c;
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int Add(int a, int b) { return a+b; } int main() { int t[]={1,2,3,4,5,6,7,8,9,10}; vector vector transform(v1.begin(), v1.end(), v2.begin(), bind2nd(ptr_fun (Add),1)); for_each(v2.rbegin(), v2.rend(), Out return 0; } Program outputs:
What will happen when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
int main() {
int t[] = { 3, 4, 2, 1, 0, 3, 4, 1, 2, 0 };
vector
multimap
for (vector
stringstream s;s << *i << *i;
m.insert(pair
}
pair
range = m.equal_range(2);
for (multimap
cout << i?>first << " ";
}
return 0;
}
The output will be:
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
template
void print(T start, T end) {
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main()
{
int t1[] ={ 1, 7, 8, 4, 5 };
list
int t2[] ={ 3, 2, 6, 9, 0 };
list
l1.sort();
list
it++; it++;
l1.splice(l1.end(),l2, it, l2.end());
print(l1.begin(), l1.end()); cout<<"Size:"< print(l2.begin(), l2.end()); cout<<"Size:"< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
int main ()
{
std::vector
for(int i = 10; i>0; i??)
{
v1.push_back(i);
}
std::vector
int sum = 0;
while(it != v1.end())
{
sum+=it++;
}
std::cout<<*v1.erase(v1.begin(),v1.end()?3)<<" "< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void print(int v) { cout< struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++; } }; bool predicate(int v) { return v%2==0; } int main() { vector generate_n(v1.begin(), 10, Sequence(1)); set remove_if(s1.begin(), s1.end(), predicate); for_each(s1.begin(), s1.end(), print);cout< return 0; } Program outputs:
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: one two three
#include
#include
using namespace std;
int main ()
{
string a;
cin>>a;
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
set
vector
swap_ranges(s1.begin(), s1.end(), v1.begin());
for_each(v1.begin(), v1.end(), myfunction);
for_each(s1.begin(), s1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
void multiply (int a) {
a*2;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
for_each(v1.begin(), v1.end(), multiply);
iter_swap(v1.begin(),t+9);
for_each(v1.begin(), v1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
multiset
s1.insert(v.begin(),v.end());
pair
range = s1.equal_range(6);
while (range.first != range.second) {
cout<<*range.first<<" "; range.first++;
}
return 0;
}
What will happen when you attempt to compile and run the code below, assuming that file test.in contains the following sequence: 1 2 3?
#include
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { ifstream f("test.in"); list for( ; !f.fail() ; ) { int i; f>>i; l.push_back(i); } f.close(); for_each(l.begin(), l.end(), Out return 0; } Programwill output:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={5,6,8,2,1}; vector sort(t1, t1+5); sort(t2, t2+5); set_difference(t1,t1+5,t2,t2+5,v1.begin()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={5,6,8,2,1}; vector sort(t1, t1+5); sort(t2, t2+5); set_union(t1,t1+5,t2,t2+5,v1.begin()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; vector v1(t, t+10); sort(v1.begin(), v1.end()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code? Choose all that apply.
#include
#include
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; fstream f("test.out", ios::trunc|ios::out); list for_each(l.begin(), l.end(), Out f.close(); f.open("test.out"); for( ; f.good() ; ) { int i; f>>i; cout< } f.close(); return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t[]={3,2,4,1,5,10,9,7,8,6}; vector sort(v1.begin(), v1.end(), greater cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
using namespace std;
template
void f(A a)
{
cout<<1< } void f(int a) { cout<<2< } int main() { int a = 1; f return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int Add(int a, int b) { return a+b; } int main() { int t[]={1,2,3,4,5,6,7,8,9,10}; vector vector transform(v1.begin(), v1.end(), v2.begin(), bind2nd(ptr_fun (Add),1)); vector cout<<*it< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
using namespace std;
template
class A {
T_v;
public:
A() {}
A(T v): _v(v){}
T getV() { return _v; }
void add(T & a) { _v+=a; }
void add(string & a) {
_v.insert(0, a);
}
};
int main()
{
A
string s(" world!");
a.add(s);
cout << a.getV() < return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out< } }; struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return 10*(1+(start++ %3)); } }; int main() { vector vector generate(v1.begin(), v1.end(), Sequence(1)); sort(v1.rbegin(), v1.rend()); unique_copy(v1.begin(),v1.end(), v2.begin()); for_each(v2.begin(), v2.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out< struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++; } }; int main() { vector vector generate(v1.begin(), v1.end(), Sequence(1)); reverse_copy(v1.begin(),v1.end(), v2.rbegin()); sort(v2.begin(), v2.end(), less_equal for_each(v2.begin(), v2.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={6,10,8,7,9}; vector sort(t1, t1+5); sort(t2, t2+5); copy(t1,t1+5,v1.begin()); copy(t2,t2+5,v1.begin()+5); merge(v1.begin(), v1.begin()+5,v1.end()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What will happen when you attempt to compile and run the following code?
#include
using namespace std;
class C {};
template
class A {
T_v;
public:
A() {}
A(T v): _v(v){}
T getV() { return _v; }
void add(T a) { _v+=a; }
};
int main()
{
A
A
a.add(C());
cout << b.getV() < return 0; }
What happens when you attempt to compile and run the following code?
#include
using namespace std;
int main()
{
cout.setf(ios::hex, ios::basefield);
cout<<100<<" ";
cout.unsetf(ios::hex);
cout<<100<<" ";
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
template
public:
B(T v):val(v){}
T getV() const {return val;} };
template template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< string tolower(const string & s) { string tmp(s); for(unsigned i = 0; i< tmp.size(); ++i){ tmp[i] = tolower(tmp[i]); } return tmp; } bool Less(const B return tolower(a.getV()) int main() { string t[]={"aaa","bbb","Aaa", "Bbb","aAa","bBb","aaA","bbB"}; vector > v1; v1.assign(t, t+8); stable_sort(v1.begin(), v1.end(), Less); for_each(v1.begin(), v1.end(), Out >(cout));cout< return 0; } Program outputs:
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: 1 2 3 4 quit
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { list while(cin.good()) { string s; cin>>s; if (s == "quit") break; l.push_back(s); } for_each(l.begin(), l.end(), Out return 0; } Program will output:
What happens when you attempt to compile and run the following code?
#include
#include
int main ()
{
std::vector
for(int i = 0; i<10; i++) {v1.push_back(i); }
std::vector
std::vector
for( ; it != v2.end(); it++) {std::cout<<*it++<<" "; }std::cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; deque sort(d1.begin(), d1.end()); deque for_each(it, d1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a):a(a) {}
int getA() const { return a;} void setA(int a){ this?>a = a;}
bool operator < ( const A & b) const { return a }; struct display { void operator() (const A & a) {cout << " " << a.getA();} }; struct add10 { void operator() (A & a) { a.setA(a.getA()+10) ;} }; int main() { int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 }; vector v1(t, t + 10); set s1(t, t + 10); for_each(v1.begin(), v1.end(), add10()); for_each(v1.begin(), v1.end(), display()); for_each(s1.begin(), s1.end(), add10()); for_each(s1.begin(), s1.end(), display()); return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
int main() {
int t[] = { 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector
map
for (vector
stringstream s;s << *i << *i;
m.insert(pair
}
pair
range = m.equal_range(6);
for (map
cout << i?>first << " ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
bool compare(int a, int b) { return a == b; }
int main () {
int t[] = {1,2,3,4,5,1,2,3,4,5};
vector
vector
int m1[] = {1, 2, 3};
while ( (it = find_first_of (it, v.end(), m1, m1+3)) != v.end()) {
cout< } cout<< endl; return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; set s1(t, t+10); sort(s1.begin(), s1.end()); for_each(s1.begin(), s1.end(), Out(cout));cout< return 0; } Program outputs:
What will be output of the program when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
int main(){
int second[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
string first[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight","zero"};
multimap
for(int i=0; i<10; i++) {
m.insert(pair
}
m[0]="ten";
m.insert(pair
for(multimap
cout<second<<" ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
B operator +(const B &b )const { return B(val + b.val);} };
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< B Add(B a, B b) { return a+b; } int main() { int t[]={1,2,3,4,5,6,7,8,9,10}; vector v1(t, t+10); vector v2(10); transform(v1.begin(), v1.end(), v2.begin(), bind2nd(ptr_fun(Add),1)); for_each(v2.rbegin(), v2.rend(), Out(cout));cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
B operator +(const B &b )const { return B(val + b.val);} };
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< template struct Add : public binary_function { A operator() (const A & a, const A & b) const { return a+b; } }; int main() { int t[]={1,2,3,4,5,6,7,8,9,10}; deque d1(t, t+10); deque d2(10); transform(d1.begin(), d1.end(), d2.begin(), bind2nd(Add(), 1)); for_each(d2.rbegin(), d2.rend(), Out(cout));cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator > (const B & v) const { return val>v.val;} };
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { int t[]={20, 30, 10, 20, 30, 10, 20, 30, 10, 20}; deque d1(t, t+10); sort(d1.begin(), d1.end(), greater()); pair for_each(result.first, result.second, Out(cout));cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out< } }; struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++ ; } }; int main() { vector generate(v1.begin(), v1.end(), Sequence(1)); set deque reverse(v1.begin(),v1.end()); reverse(s1.begin(), s1.end()); reverse(d1.begin(), d1.end()); for_each(v1.begin(), v1.end(), Out for_each(s1.begin(), s1.end(), Out for_each(d1.begin(), d1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
int calculate(T start, T end)
{
int s = 0;
while (start != end)
s+= *start; start++;return s;
}
int main ()
{
int t[] = {1, 2 ,3 ,4 ,5, 6 , 7, 8 , 9, 10};
vector
deque
cout< cout< cout< cout< cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
B operator ?(const B &b )const { return B(val ? b.val);}};
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { B t1[]={1,2,3,4,5,6,7,8,9,10}; B t2[]={1,2,3,4,5,6,7,8,9,10}; vector v1(t1, t1+10); vector v2(t2, t2+10); vector v3(10); transform(v1.begin(), v1.end(), v2.rbegin(), v3.begin(), minus()); for_each(v3.rbegin(), v3.rend(), Out(cout));cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { B t1[]={3,2,4,1,5}; B t2[]={6,10,8,7,9}; vector v1(10,0); sort(t1, t1+5); sort(t2, t2+5); copy(t1,t1+5,v1.begin()); copy(t2,t2+5,v1.begin()+5); inplace_merge(v1.begin(), v1.begin()+5,v1.end()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out< } }; struct Sequence { int start; Sequence(int start):start(start){} int operator()() { return start++; } }; struct Odd { bool operator()(int v) { return v%2==0; }}; int main() { vector generate(v1.begin(), v1.end(), Sequence(1)); partition(v1.begin(),v1.end(), Odd()); for_each(v1.begin(), v1.end(), Out return 0; } Choose all possible outputs:
What will happen when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class A
{
int a;
public:
A(int a) {this?>a = a; c++;}
~A() { c??;}
static int c;
};
int A::c(0);
int main ()
{
A t[] = {0, 1, 2, 3, 4, 5, 6, 7, 8 , 9};
vectorv1(t, t+10);
dequed1(v1.begin(), v1.end());
deque d2;
d2 = d1;
cout< return 0; } How many objects of type A will be created:
What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: one two three
#include
#include
using namespace std;
int main ()
{
string a;
getline(cin, a);
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int t[] ={ 1, 1, 2, 2, 3, 3, 4, 4, 5, 5 };
list
multiset
if (s1.count(3) == 2) {
s1.erase(3);
}
for(multiset
cout<<*i<<" ";
}
return 0;
}
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int multiply (int a) {
return a*2;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector
set
transform(s1.begin(), s1.end(), v1.begin(), multiply);
transform(v1.begin(), v1.end(), s1.begin(), multiply);
for_each(s1.begin(), s1.end(), myfunction);
return 0;
}
Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a) : a(a) {}
int getA() const { return a; } void setA(int a) { this?>a = a; }
};
struct Even {
bool operator ()(const A & a, const A &b) {
return (a.getA() % 2)==b.getA() % 2;
}
};
int main () {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
deque
deque
cout<< it?d.begin()< return 0; } Program outputs:
What will happen when you attempt to compile and run the following code? Choose all that apply.
#include
#include
#include
#include
using namespace std;
class A {
int a;
public:
A(int a) : a(a) {}
int getA() const { return a; } void setA(int a) { this?>a = a; }
bool operator < (const A & b) const { return a }; class F { A val; public: F(A & v):val(v){} bool operator() (A & v) { if (v.getA() == val.getA()) return true; return false; } }; int main() { int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 }; vector v1(t, t + 10); set s1(t, t + 10); A a(6); F f(a); find_if(s1.begin(), s1.end(), f); if (find_if(v1.begin(), v1.end(), f) !=v1.end()) { cout<<"Found!\n"; } else { cout<<"Not found!\n"; } return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; int t1[]={1,2,3,4}; deque set sort(d1.begin(), d1.end()); cout< < return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main(){
int second[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 10 };
string first[] = {"three", "four", "two", "one", "six","five", "seven", "nine","eight"," ten"};
map
for(int i=0; i<10; i++) {
m.insert(pair
}
if (m[11] == "eleven") {
cout<<"eleven ";
}
for(map
cout<second<<" ";
}
cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
int main() {
int t[] = {1,2,3,2,3,5,1,2,7,3,2,1,10, 4,4,5};
vector
set
pair
cout<<*resultSet.first<<" "<<*resultSet.second< return 0; } Program outputs: